Question

multimea solutiilor ecuatiei este egala cu
(2x-3)la putea 2 =121

Answer 1

(2x-3)²=121 => 2x-3=+/-11 =>2x=+/-11+3=>$x= \frac{+/-11+3}{2}$
=> x apartine multimii {-$\frac{11+3}{2}=7$, $\frac{11-3}{2}=4$
x∈{7,4}