Question

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..........multumesc ​

Answer 1

Explicație pas cu pas:

$\Big( \sqrt{6} - \dfrac{1}{2} i\Big)\Big( \dfrac{ \sqrt{6} }{2} + \dfrac{ \sqrt{3} }{2} i\Big) = \\ = 3 + \dfrac{3 \sqrt{2} }{2}i - \dfrac{ \sqrt{6} }{4}i - \dfrac{ \sqrt{3} }{4} {i}^{2}\\ = 3 + \dfrac{6 \sqrt{2} }{4}i - \dfrac{ \sqrt{6} }{4}i + \dfrac{ \sqrt{3} }{4} \\ = \dfrac{12 + \sqrt{3} }{4} + \dfrac{\sqrt{2}(6 - \sqrt{3})}{4}i$