Question

Mulțumesc!!!!!!!!!!!!!!!​

Answer 1

$p=2^{44}+2^{23}+1\\ \\ p=2^{22\cdot 2}+2^{22+1}+1\\ \\ p=(2^{22})^2+2^{22}\cdot 2 +1\\ \\ p=(2^{22})^2+2\cdot 2^{22}\cdot 1 +(1)^2\\ \\ p=(2^{22}+1)^2 \Rightarrow p \ este \ patrat \ perfect\\ \\ \boxed{(a+b)^2=a^2+2ab+b^2}$

Answer 2

Răspuns:

p=1+2²³+2⁴⁴=(1+2²²)² ;  a²+2ab+b²=(a+b)²

Explicație pas cu pas: