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Răspunsuri la întrebare
Pt.m1:Vectorial:F+N1+G1+Ff1+T=m1a
Scalar:Ox:F-m1gsinα-Ff1-T=m1a
Oy:N1-m1gcosα=0=>N1=m1gcosα
Ff=μN1=μm1gcosα
F-m1gsinα-μm1gcosα-T=m1a (1)
pt.m2:Vectorial:T+N2+G2+Ff2=m2a
Scalar:Ox:T-m2gsinα-Ff2=m2a
Oy:N2=m2gcosα
Ff=μN2=μm2gcosα
T-m2gsinα-μm2gcosα=m2a (2)
(1)+(2)=>F-m1gsinα-μm1gcosα-T+T-m2gsinα-μm2gcosα=a(m1+m2)<=>F-gsinα(m1+m2)-μgcosα(m1+m2)=a(m1+m2)=>a=[F-gsinα(m1+m2)-μgcosα(m1+m2)]/(m1+m2)=(30-10*3*0,5-0,1*10*0,866*3)/3=(30-15-2,59)/3=12,4/3=4,13 m/s²
T-m2gsinα-μm2gcosα=m2a=>T=m2a+m2gsinα+μm2gcosα=2*4,13+2*10*0,5+0,1*2*10*0,866=8,26+10+1,732=19,992 N
pt.m2 cand coboara liber: N2+G2+Ff2=m2a'
Scalar:Ox:m2gsinα-Ff2=ma
Oy:N2=m2gcosα
Ff2=μN2=μm2gcosα
m2gsinα-μm2gcosα=m2a'=>a'=(m2gsinα-μm2gcosα)/m2=(2*10*0,5-0,1*2*10*0,866)/2=8,26/2=4,13 m/s²