Question

Multumesc anticipat !

Answer 1

A={x ∈ Z | $\frac{9}{x-3}$ ∈ Z } => x-3 este divizor de 9

x-3 ={ 1,3,9} |+3

x=4,6,12

A={4;6;12}

B={x ∈ Z | 6|x sau 4|x } => x este multiplu de 6 si 4

x = {12,24,36,...}

B={12;24;36;...}

A∩B={12}