Question

n=1×2×3×4×......×49×50+23​

Answer 1

n = 1×2×3×4×......×49×50 + 23​

facem un artificiu

n = (1×2×3×4)×5×..×49×50 + 23

n = 24×(5×..×49×50) + 23

notam (5×..×49×50) cu x

n = 24x + 23

n : 24 = x + rest 23

restul impartirii este 23