Question

(n+1) + (n+3) + (n+5) + ... + (n+101)=2652

Answer 1

Aflam numarul termenilor
T1=n+1
T2=n+3=n+1+2
T3=n+5=n+1+2+2
Tn=n+1+2*(n-1)
n+1+2*(n-1)=n+101
1+2(n-1)=101
2(n-1)=100
n-1=50
n=51
Se calculeaza:
1+3+5+......+101
Sunt 51 termeni
51^2=2601
51n+2601=2652
51n=51
n=1