Question

N= ?
13/ (nla puterea 3-3la puterea n )
Am nevoie Urgentttt!!

Answer 1

   
[tex]\displaystyle \frac{13}{n^3 -3^n} \\ \\ n=0 ~~\Longrightarrow~~\frac{13}{0^3 -3^0} =\frac{13}{ -1} = \boxed{-13 \in Z} \\ \\ n=2 ~~\Longrightarrow~~\frac{13}{2^3 -3^2} =\frac{13}{ 8-9} = =\frac{13}{ -1}= \boxed{-13 \in Z} \\ \\ } \Longrightarrow ~~ \boxed{n_1 = 0~~si~~n_2=2} [/tex]