Question

n={3^13:[(3*2^20-2^20)^2:16^10-2^0]^11+3^0}:10
Calculați n^2020

Answer 1

Răspuns:

n²⁰²⁰=1

Explicație pas cu pas:

n={3¹³:[(2²¹)²:2⁴⁰-1)]¹¹+1}:10=[3¹³:(4-1)¹¹+1]:10=(3¹³:3¹¹+1):10=(3²+1):10=(9+1):10=10:10=1

n²⁰²⁰=1²⁰²⁰=1