Question

n/9 = a rest 7, n/8 = b rest 5. cat este restul lui 72:n ?

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Answer 1

$\frac{n}{9} =a+7=> n=9a+56\\\frac{n}{8} =b+5=>n=8b+40\\72:n=72:(9a+56)=\frac{8}{a} +\frac{9}{7} \\72:n=72:(8a+40)=\frac{8}{b} +\frac{9}{5}$

Deci resturile sunt :$\frac{9}{7} \frac{9}{5}$.