Question

n la orice putere tiinde spre 0 sau spre infinit?

Answer 1

[tex] \lim_{n \to \infty} \frac{3n^2+10}{4n^2+10n-3} = \lim_{n \to \infty} \frac{n^2(3+10/n^2)}{n^2(4+10/n-3/n^2)}=\\ = \lim_{n \to \infty} \frac{3+10/n^2}{4+10/n-3/n^2}= \frac{3}{4} [/tex]