Question

n la puterea 3 = 27

( n+1) la puterea 3 = 125

urgent !! Dau coroana !!

Answer 1

    
[tex]1) \\ n^3 = 27 \\ n^3 = 3^3 \\ n= \sqrt[3]{3^3}=\boxed{3} \\ \\ \\ 2) \\ (n+1)^3= 125 \\ (n+1)^3= 5^3 \\ n+1 = \sqrt[3]{5^3} \\ n+1 = 5 \\ n=5-1 = \boxed{4}[/tex]