Question

n²-11n-26=0
ajutooooooooor​

Answer 1

metoda 1:

delta=(-11)^2-4*(-26)*1=121+104=225

n=(11+-radical din 225)/2

n=(11+-15)/2

n1=(11+15)/2=26/2=13

n2=(11-15)/2=-4/2=-2

metoda 2:

n^2-13n+2n-26=0

n(n-13)+2(n-13)=0

(n-13)(n+2)=0

n-13=0 => n=13 sau n+2=0 => n=-2