Question

nevoie de ajutor rapid

Answer 1

$\it 5x-8\geq2x+3 \Rightarrow 5x-2x\geq3+8 \Rightarrow 3x\geq11 \Rightarrow x\geq\dfrac{11}{3} \Rightarrow A=\Big[\dfrac{11}{3},\ \infty\Big)\\ \\ \\ \dfrac{2x+3}{5}<1 \Rightarrow 2x+3<5|_{-3} \Rightarrow 2x<2|_{:1} \Rightarrow x<1 \Rightarrow B=(-\infty,\ 1)\\ \\ \\ -4\leq3x+2<7|_{-2} \Rightarrow -6\leq3x<5|_{:3} \Rightarrow -2\leq x<\dfrac{5}{3} \Rightarrow C=\Big[-2,\ \dfrac{5}{3}\Big)$

$\it |x+1|<\sqrt5 \Rightarrow -\sqer5<x+1<\sqrt5|_{-1} \Rightarrow -1-\sqrt5<x<-1+\sqrt5 \Rightarrow \\ \\ \\ \Rightarrow D=(-1-\sqrt5,\ \ -1+\sqrt5)$

$\it -1\leq\dfrac{5x-6}{2}<3|_{\cdot2} \Rightarrow -2\leq5x-6<6|_{+6} \Rightarrow 4\leq5x<12|_{:5} \Rightarrow \\ \\ \\ \Rightarrow \dfrac{4}{5}\leq x<\dfrac{12}{5} \Rightarrow 0,8\leq x<2,4 \Rightarrow E=[0,8;\ \ 2,4)$