Question

Nr 2 roman . Cu A sau F

Answer 1

$II.1)A$

$\frac{3}{5} = \frac{9}{15} = > 3 \times 15 = 5 \times 9 = > 45 = 45 \: A$

$2)A$

$3)A$

$\frac{15}{100} \times 300 = 45$

$15 \times 3 = 45 \:$

$45=45 \:A$