Question

Nr naturale a si b sunt consecutive cu b<a.Aflati valorile expresiilor : a)10*a-5*(a-b)*(a+b). b) ab-ba

Answer 1

b < a => a=b+1

10×(b+1)-5×(b+1-b)×(b+1+b)=

=10b+10-5×1×(2b+1)=

=10b+10-10b+5

10b-10b=0 => 10-5=5