Question

Nu am idee cum sa o fac ​

Answer 1

ABCD trapez dreptunghic <A și<D =90°

AC _l_BC;AB=24,cm DC=6cm

a)AD=CE

∆ABC dreptunghic

înălțimea CE =√AE×EC=√6×18=6√3cm

=>AD=6√3cm

b) aria ABCD=15/16×ariaMAB

ADnBC=M

aria ABCD=(AB+CD)AD/2=(6+24)6√3/2=

30×3√3=90√3cm²=6×15√3cm²

ariaMAB

∆ACM dreptunghic ,CD înălțime

CD²=MD×AD=>MD=6²/6√3=6√3/3=2√3cm

MA=AD+MD=6√3+2√3=8√3cm

ariaMAB=AB×AM/2=24×8√3/2=12×8√3=

96√3cm²=6×16√3cm²

aria ABCD=6×15√3 unde 6√3=aria ABCD/15

ariaMAB=6×16√3cm². unde6√3=ariaMAB/16

aria ABCD/15=ariaMAB/16

aria ABCD=15/16×ariaMAB