Question

NU IGNORATI E FOARTE URGENTTT INCEPE ȘCOALĂ SI EU NU AM TERMINAT TEMELE!!!!!



2. Efectuați calculele:
b) {[(2^15•3^13•5^7):(2^13•3^12•5^5) - 2^4•3:8]: 49-2}: 2019^0,
c) (3•10^3+ 2•10^2 + 4): 3^2•2+ [20+ (202 : 2 - 51) - 2019^0).​

Answer 1

{([2^2x3x5^2)-2^4x3:8]:49-2}: 1
{[(4•3•25)-16•3:8]:49-2}
[300-48:8]:49-2
(300-6):49-2
294:49-2
6-2
4


(3•1000+2•100+4):9•2+[20+(101-51)-1]
(3000+200+4):9•2+[20+150-1]
3204:9•2 +169
356•2+169
712+169
881



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