Question

Numai primul și al treilea exercițiu

Answer 1

√336+√575−√189−√828=√21−√23
(x+2y^2)(x^2-2xy^2+4y^4)(x^6-8x^3y^6+64y12=((x+2y^2)(x2−2xy^2+4y^4))(x6+−8x^3y6+64y^12)=((x+2y^2)(x^2−2xy^2+4y^4))(x^6)+((x+2y^2)(x^2−2xy^2+4y^4))(−8x^3y^6)+((x+2y^2)(x^2−2xy^2+4y^4))(64y^12)=8x^6y^6+x^9−64x^3y^12−8x^6y^6+512y^18+64x^3y^12=512y^18+x^9

Answer 2

1)rad 336 + rad 575 - rad 189 -rad 828 =4 rad 21 + 5 rad 23 - 3 rad 21 - 6 rad 23 = rad 21- rad 23
3)(x + 2y^2)(x^2 - 2xy^2 + 4 y^4)(x^6 - 8 x^3y^6 + 64 y^12)=
(x+2y^2)(x-2y^2)(x^3- 8y^6)=(x^2 +4y^4)(x^3- 8y^6)
Sper ca te-am ajutat...