Question

Numarul 1420 se imparte in parti invers proportionale cu numerele 3, 5, 7​

Answer 1

3x=5y=7z=k

x=k/3

y=k/5

z=k/7

k/3 + k/5 + k/7 = 1420

35k+21k+15k=1420•105

71k=1420•105

k=(1420•105)/71

k=2100

x=700

y=420

z=300