Question

Numarul (7-radical din 3)^2 calculat este:"

Answer 1

[tex](7- \sqrt{3})^{2}= 7^{2}-2*7* \sqrt{3}+ \sqrt{ 3^{2} }=49-14 \sqrt{3}+3=52-14 \sqrt{3} .[/tex]

Answer 2

$(7- \sqrt{3} )^2=7^2-2 \cdot 7 \cdot \sqrt{3} + \sqrt{3} ^2=49-14 \sqrt{3} +3=52-14 \sqrt{3}$