Question

numărul de atomi de oxigen din 620 de g de acid carbonic​ URGENT OFER MEDALIE

Answer 1

Răspuns:

MH2CO3=2AH+AC+3AO=2×1+12+3×16=2+12+48=62g/mol

62g H2CO3......................48g O

620 g H2CO3......................X

X=48×620/62=480g O

N=n×N,A

n=m/A

n=480g/16g/mol=30moli O

N=30×6,022×10²³=180,66×10²³ atomi de O sau 1,8066×10²⁵ atomi de O