Question

Numărul de izomeri care prezintă atom de carbon asimetric, ai unei hidrocarburi aciclice care contine 14,28% hidrogen si are masa molara 84 g/mol este:
A. 1
B. 2
C. 3
D. 4
E. Nici unul​

Answer 1

Explicație:

H% = 14.28%

C% = 100 - 14.28 = 85.72%

C : H = 85.72/12 : 14.28/1 = 7.14 : 14.28

C : H = 1 : 2 ---> CnH2n

M = 12n + 2n = 14n

M = 84 g/mol

14n = 84

n = 6 ----> C6H12

1)C=C-C-C-C-C

2)C-C=C-C-C-C

3)C-C-C=C-C-C

4)C=C-C-C-C

|

C

5)C=C-C-C-C

|

C

6)C=C-C-C-C

|

C

7) C-C=C-C-C

|

C

8) C-C=C-C-C

|

C

9) C-C=C-C-C

|

C

10)C=C-C-C

| |

C C

C

|

11)C=C-C-C

|

C

C

|

12)C=C-C-C

|

C

13)C-C=C-C

| |

C C

C

|

14)C-C=C-C

|

C