Question

numarul de moli de carbonat de magneziu continut in 168 g de carbonat de magneziu de puritate 90%

Answer 1

M,MgCO3=84g/mol

calculez masa de carbonat pur

p= m,px100/mi---> m,p=168x90/100= 151,2g

calculez nr.moli

niu= m/M= 151,2g/ 84g/mol= .......................calculeaza!!