Question

numărul natural n din egalitatea 5,6-n×24+1 supra 5=4,2
a)1
b)0,25
c)0,5
d)1,4

Answer 1

5,6-n×24+1/5=4,2
28/5-24n +1/5 = 4,2
29/5-24n = 4,2
-24n = 4,2-29/5
-24 n= 21/5-29/5
-24n = -8/5
n= -8/5:(-24)
n= 8/5×1/24
n = 1/5×1/3
n= 1/15
n= 0,0(6)