Question

Numerele 127 ,53 si 76 impartite la acelasi numar natural ,,n,, dau resturile 7 ,5 si respectiv 4 determinati numarul ,,n,,

Answer 1

127: n= c1+7
53: n=c2+5
76: n=c3+4

127-7=c1*n
53-5= c2*n
76-4=c3*n

120:n=c1
48:n=c2
72:n=c3

120=2³*3*5
48=2⁴*3
72=2³*3²
cmmdc=2³*3=24

127:24=5, rest7
53:24=2, rest 5
76:24= 3, rest 4

n=24