Question

Numerele 253, 325 si 181 impartite la acelasi numar natural dau restul 13, 5 ,1

Answer 1

253:x=c+r13 => x*c=253-13=240 => x*c=2^4*5*3
325:x=c1+r5 => x*c1=325-5=320 => x*c1=2^6*5
181:x+c2+r1 => x*c2=181-1=180 => x*c2=2^2*3^2*5

=> x=2^2*5=4*5=20
c=2^2*3=12
c1=2^4=16
c2=3^2=9

Proba
253:20=12 r13
325:20=16 r5
181:20=9 r1