Question

numerele 271,356 si 534 impartite la acelasi numar diferit de zero dau resturile 7,8 si 6.sa se afle acest numar

Answer 1

271 : n = a R = 7. -> 271 = na + 7
356 : n = b R = 8. -> 356 = nb + 8
534 : n = c. R = 6. -> 534 = nc + 6

271 - 7 = na. 264 = na
356 - 8 = nb. -> 348 = nb
534 - 6 = nc. 528 = nc

n = { (264; 348; 528) }
264 | 2. 356 | 2. 534 | 2
132 | 2. 178 | 2. 267 | 3
66 | 2. 89 | 89. 89 | 89
33 | 3. 1 | 1 |
11 | 11
1 |
264 = 2 la puterea 3 x 3 x 11
356 = 2 la puterea 2 x 89
534 = 2 x 3 x 89

c.m.m.d.c = 6 => n = 6