Question

Numerele a si b sunt direct proportionale cu 2 si 3. calvulati valoarea raportului 2a+3b/a+b

Answer 1

{a,b}d.p{2,3}⇒a/2=b/3
Deci 3a=2b⇒a=2b/3
$\frac{2a+3b}{a+b}=\frac{2*\frac{2b}{3}+^{3)}3b}{\frac{2b}{3}+^{3)}b}= \\ \\\frac{\frac{4b+9b}{3}}{\frac{2b+3b}{3}}=\frac{13b}{3}*\frac{3}{5b}= \bold{\frac{13b}{5b}}$