Question

Numerele naturale a,b,c sunt direct proportionale cu 2;3 , respectiv 5.
A). Cat la suta din numarul a reprezinta numarul b ?
B). Aflati numerele a,b,c stiind ca $(a-b)^{2}$+$(b-c)^{2}$+$(c-a)^{2}$=56

Answer 1

a=2k
b=3k
c=5k

x/100a=b?
2kx/100=3k
2kx=300k
x=300:2
x=150 
150/100=1.5%

b) (a-b)^2+(b-c)^2+(c-a)^2=56
(2k-3k)^2+(3k-5k)^2+(5k-2k)^2=56
(-k)^2+(-2k)^2+(3k)^2=56
k^2+4k^2+9k^2=56
14k^2=56
k^2=4
k=2

a=2*2=4
b=3*2=6
c=5*2=10