Question

numerele naturale x,y si z au suma 48.Aflati numerele,stiind ca x-1,y si z+1 sunt direct proporționale cu 4,5 si 7

Answer 1

x+y+z=48
(x-1)/4 = y/5=(z+1)/7=k
(x-1)/4 = k => x=4k+1
y/5=k => y=5k
(z+1)/7=k => z=7k-1
x+y+z= 4k+1+5k+7k-1 =16 k = 48 => k=48/16 = 3
=> x=4*3+1=13
y=5*3=15
z=7*3-1 =20