Question

Numerele naturale x,y,z sunt invers proporționale cu nr. 0,1 ; 0,2 ; 0,3 , iar 3x+2y+5z=110. Aflați nr. x , y și z.
Va rog, Repede!!!

Answer 1

x/10=y/5=z/(10/3)=k
x/10=k⇒x=10k
y/5=k⇒y=5k
z/(10/3)=k⇒z=10k/3
3x+2y+5z=110
3·10k+2·5k+5·10k/3=110
30k+10k+50k/3=110
40k+50k/3=110
120k+50k=330
170k=330
k=330/170
k=33/17
x=330/17
y=165/17
z=110/17

Answer 2

{x,y,z}ip{0,1;0,2;0,3}
{x,y,z}ip{1/10, 1/5,3/10}
x/10=y/5=3z/10=k
x=10k
y=5k
z=10k/3
3x+2y+5z=110
30k+10k+50k/3=110
90k+30k+50k=330
170k=330
k=33/17
x=330/17
y=165/17
z=330/51=110/17