Question

numerele x,y,z sunt direct proportionale cu 2,6,9. a) cat la suta reprezinta numarul cel mare din diferemta celorlalte doua? b) determinati numerele daca 2z/27 -- y/18 -- x/12=9

Answer 1

x/2=y/6=z/9=k
x=2k
y=6k
z=9k
2*2k/27-6k/18-2k/12=9
4k/27-k/3-k/6=9/*54
8k-18k-9k=486
-19k=486
k= -25,57
x=2*(-25,57)= -51,14
y=6*(-25,57)= -153,42
z=9*(-25,57)= -230.13
-153,42-(-230,13)=76,71
(76,71*(-51,14))/100= -39,22%