Question

O autospeciala arunca 0.6m cubi de apa pe minut.Calculeaza greutatea apei aruncate într-o jumătate de ora (p=1g/cm cub, g=9.8N/Kg)Dau funda. Mulțumesc anticipat

Answer 1

[tex]\displaystyle Se~da:\\ \\ v=0,6\frac{m^3}{min}=0,01\frac{m^3}{s}\\ \\ t=0,5h=1800s\\ \\ \rho=1\frac{g}{cm^3}=1000\frac{kg}{m^3}\\ \\ g=9,8\frac{N}{kg}\\ \\ G=?N\\ \\ \\[/tex]


[tex]Formule:\\ \\ G=m\times g\\ \\ \\ m=V\times \rho\\ \\ \\ V=v\times t\\ \\ \\ G=v\times t\times \rho\times g\\ \\ \\ Calcule:\\ \\ G=0,01\times 1800\times 1000\times 9,8=176400N[/tex]