Question

o bila cu m=1kg are la un moment dat impulsul mecanic de 20N*s. Aflati Ec la acel moment

Answer 1

   
[tex]\displaystyle\\ \overrightarrow{p}=\overrightarrow{F}\Delta t =20N\cdot s = m\overrightarrow{v}=20Kg\cdot metri/s\\\\ \overrightarrow{v}= \frac{20}{m}= \frac{20}{1}= 20~metri/s\\\\ Ec= \frac{m v^2}{2}= \frac{1\cdot 20^2}{2}= \frac{400}{2}=200~J [/tex]