Question

o brutarie trimite in trei magazine 2000 de paini . Dupa ce fiecare magazin vinde acelasi numar de paini,la primul magazin mai raman 97 de paini ,la al doilea 102,iar la al treilea 85 de paini .Cate paini a primit fiecare magazin ?

Answer 1

a+b+c=2000
a facem un segment +97
b in segment+102
c un segment+85
97+102+85=1716
1+1+1=3 segmente egale
1716:3=572o parte
a=572+97=669
b=572+102=674
c=572+85=657
a=669
b=674
c=657

Answer 2

a=primul magazin
b=al doilea magazin
c=al treilea magazin
(Asa voi nota magazinele)
a ____,97
b____,120
c____,85
(In total 2000 de paini)
Aflam cate paini s-au vandut in total.
2000-(97+120+85)=2000-302=1698
Aflam cate paini a vandut fiecare magazin.
1698:3=566
Aflam cate paini a primit magazinul a.
566+97=663
Aflam cate paini a primit magazinul b.
566+120=686
Aflam cate paini a primit magazinul c.
566+85=651
RASPUNS: primul a primit 663,al doilea 686, al treilea 651.