Question

O bunica are trei nepoti:Andrei de 4 ani,Bogdan de 6 ani si Costel de 10 ani.Bunica imparte 372 de bomboane celor trei nepoti invers proportional cu varsta fiecarui.Aflati cate bomboane a primit fiecare.

Answer 1

4, 6, 10 i.p. x, y, z
x, y, z- nr de bomboane primite de fiecare copil
x+y+z=372
4x=6y=10z=k
x=k/4
y=k/6
z=k/10
k/4+k/6+k/10=372 |·60
15k+10k+6k=22320
31k=22320
k=720
x=720/4=180 bomboane Andrei
y=720/6=120 bomboane Bogdan
z=720/10=72 bomboane Costel
verificare 180+120+72=372
Raspuns: Andrei primeste 180 bomboane, Bogdan - 120, iar Costel (cel mai mare primeste cele mai putine) - 72.

Answer 2

(4, 6, 10) i p (x, y, z)
4x= 6y = 10z = k
x = k/4
y = k/6
z = k/10
k/4 + k/6+ k/10 = 372
15k/60 + 10k/60 + 6k/60 = 22320/60
31k/60 = 22320/60
31k = 22320
k = 720
x = 720 / 4 = 180 bomboane
y = 720 / 6 = 120 bomboane
z = 720/10 =    72 bomboane