Question

O butelie de capacitatea V=25 l contine dioxid de carbon la presiunea de 5 atm si temperatura de 17 °C. Calculeaza masa dioxidului de carbon din butelie si volumul ocupat de aceasta in conditii normale de presiune si temperatura. (R=8,31 J/mol·K)
???????????? pls

Answer 1

Se da:
V=25l=0,025m³
M=0,044kg/mol
p=5atm=506625Pa
T=17°C=290K
R=8,31J/mol×K
p0=101325Pa
T0=273K
m=?kg
V0=?m³

Formule:
Din ecuatia lui Mendeleev-Clapeyron:

1)p×V=ν×R×T
p×V=m×R×T/M
m=p×V×M/R×T

2)p0×V0=ν×R×T0
p0×V0=m×R×T0/M
p0×V0=p×V×M×R×T0/R×T×M
p0×V0=p×V×T0/T
V0=p×V×T0/T×p0

Calcle:
m=506625×0,025×0,044/8,31×290≈0,231kg
V0=506625×0,025×273/290×101325≈0,1177m³