Question

O camila parcurge in prima zi 1/4 din drum, a doua zi 1/2 din rest iar in ultima zi iau ramas de parcurs 25 km. Care este lungimea totala a drumului?

Answer 1

$x\to lungimea \ drumului \\\\ \frac{1}{4} \ din \ x \to \frac{1}{4}*x = \frac{x}{4} -prima \ zi \\\\\\ x^{(4}-\frac{x}{4}=\frac{4x-x}{4} \to \frac{3x}{4} -restul \\\\ \frac{1}{2} \ din \ \frac{3x}{4} = \frac{1}{2} * \frac{3x}{4} \to \frac{3x}{8} - a \ doua \ zi \\\\ \frac{3x}{4}^{(2} -\frac{3x}{8}= \frac{6x-3x}{8} \to \frac{3x}{8} -noul \ rest \\\\ \frac{3x}{8}=25 \\\\\\ x=\frac{8*25}{3} \\\\ x=\frac{200}{3} \\\\ \boxed{x=66,6}$

Answer 2

Prima zi : 1/4x
A doua zi: (x-1/4) :2=3/4*x : 2= 3/8*x
A treia zi: 25 km

Adunam cele trei distante:

1/4*x+3/8*x+25= x2x+3x+200=8x3x=200x= 66, 6666666667