Question

O cantitate ce cuprinde 6,023 x 10^24 molecule CO2 se barboteaza in apa de var Ca(OH)2 . Aflati numarul de moli de precipitat formati

Answer 1

$\diplaystyle\mathtt{nr \ moli \ CO_2=\frac{6,023\cdot10^{24}}{6,023\cdot10^{23}}=10} \\ \\ \mathtt{Ca(OH)_2+CO_2=CaCO_3\downarrow+H_2O}$

$\mathtt{1 \ mol \ CO_2..........1 \ mol \ CaCO_3}}$

$\mathtt{10 \ moli \ CO_2..........x \ moli \ CaCO_3} \\ \\ \mathtt{x=10 \ moli \ CaCO_3}$