Question

O dizaharida are compozitia procentuala de masa 42,1%C ;6,43%H ; 51,46%O si masa molara =342 g/mol.Determinati formula moleculara a dizaharidei.

Answer 1

                                        :3,21635
C: 42,1/12=3,5083               1,09
H: 6,43/1=6,43                    2
O: 51,46/16=3,21635           1
M(C1,09H2O)n=13,09+2+16=31,09n=342 => n=11
f.m: C12H22O11