Question

o ferma agricola a insamintat in prima zi 5/14 dintr-un teren, a doua zi 5/12 din rest, a treia zi 3/7 din noul rest, iar a patra zi - restul de 60 ha. aflati suprafata arata in cele 4 zile?

Answer 1

A=A*(5/14)+[A-A*(5/14)]*(5/12)+{A-[A-A*(5/14)]*(5/12)}*3/7+60;
A=A*(5/14)+A*(9/14)*(5/12)+[A-A*(9/14)*(5/12)]*3/7+60;
A=A*(5/14)+A*(40/210)+[A-A*(40/210)]*3/7+60;
A=A*(5/14)+A*(40/210)+A*(170/210)*3/7+60;
A=A*(5/14)+A*(4/21)+A*(17/21)*(3/7)+60;
A=A*(5/14)+A*(4/21)+A*(51/147)+60;
A=A*(5/14)+A*(4/21)+A*(17/49)+60;
A=A*[(21*5)/(21*14)+(14*4)/(14*21)+(6*17)/(6*49)]+60;
A=A*[(21*5)/(294)+(14*4)/(294)+(6*17)/(294)]+60;
A=A*[(105)/(294)+(56)/(294)+(102)/(294)]+60;
A=A*(105+56+102)/(294)+60;
A=A*263/294+60;
A-A*263/294=60;
A(1-263/294)=60;
A(31/294)=60;
A=60*294/31
e ciudat rezultatul... sigur e corect enuntul tau?