Question

O gradina in forma de trapez cu baza mica de 12 cm ,baza mare de doua ori si jumatate mai mare ca baza mica iar celelante laturi egale cu 4 supra 3 sin baza mica si respectiv 1 supra 7 din suma bazelor Urgent am nevoiee !!!!

Answer 1

b=12cm;
B=2,5·12cm⇒B=30cm;
⇒l1=4/3 ·12cm
⇒l1=4·12cm/3
⇒l1=4·4cm
⇒l1=16cm;
⇒l2=1/7 ·[12cm+30cm]
⇒l2=1/7 ·42cm
⇒l2=6cm;
⇒P trapez=b+B+l1+l2
⇒P trapez=12cm+30cm+16cm+6cm
⇒P trapez=42cm+22cm
⇒P trapez=64cm[perimetrul trapezului];