Question

O hidrocarbura are raportul de masa C:H = 5:1 , iar 0.05 moli reprezinta 3.6g. Scrie si denumeste izomerii hidrocarburii.

Answer 1

n=m/M => M=m/n=3,6g/0,05mol=72g/mol
notam formula CxHy
12x/y=5/1 => 12x=5y => y=2,4x
Mhidrocarbura=12x+y=72
12x+2,4x=14,4x=72 => x=5
y=2,4*5=12
f.m: C5H12 - pentanul
n-pentan, izobutan(2-metil-butan) si neopentan(2,2-dimetil-propan)