Question

o naveta spatiala cu lungimea proprie lo=90m se aproprie de pamant cu viteza v=0,2c.
determina lungimea navetei pe care o masoara un pamantean.

Answer 1

$l=l_o*\frac{1}{\gamma} \\\\beta=\frac{v}{c}=\frac{0,2c}{c}=0,2\\ \gamma=\frac{1}{\sqrt{1-\beta^2 }}=\frac{1}{\sqrt{1-0,2^2}}=\frac{1}{\sqrt{0,96}}=\frac{1}{0,979}\approx1,021\\ l=l_o*\frac{1}{\gamma}=90*\frac{1}{1,021}=88,14m\\ l=88,14m$