Question

o proba de 12.9 g produs organic care contine C ,H,Cl da la analiza 28.7 g clorura de argint .17.6 g CO2 si 9 g apa .Stiind ca in molecula se gaseste un singur atom de clor determinati formula moleculara .

Answer 1

M(miu)=18g/molH2O
M,CO2= 44g/mol
M,AgCl= 143,5g/mol
calculez moli din fiecare substanta data
niu(n)= m/M
n,AgCl= 28,7g/143,5g/mol= 0,2mol AgCl---> 0,2mol Cl
n,H2O=9g/18g/mol= 0,5molH2O------. >1molH
n.CO2=17,6g/44g/mol=0,4molCo2---> 0,4molC
IMPARTIND prin cel mai mic numar, reazulta; C2H5Cl