Question

O proba de 200 g de zinc de puritate 91% reactioneaza cu o solutie de acid clorhidric de concentratie 36,5%.
Calculati volumul solutiei de acid clorhidric de concentratie procentuala exprimata in mL stiind ca densitatea acidului clorhidirc=18,1g/cm3

Answer 1

puritatea = m pur/m impur *100 => m pur = puritatea* m impur/100 = 91*200/100=182g Zn

Zn + 2HCl = ZnCl2 + H2

MZn=65g/mol

MHCl=AH+ACl=1+35,5=36,5g/mol

65g Zn...............2*36,5g HCl
182g Zn..................x=204,4g

Cp=md/ms*100=>ms=md*100/Cp=204,4*100/36,5=560g sol. HCl

ro=ms/V=>V=ms/ro=560g/18,1g.cm3=30,93922cm3 HCl

1cm3=1mL

ro-densitatea

M(miu), masa molara, g/mol

A- masa atomica

Daca ai nevoie de alte explicatii, ai com.