Question

O proba de butadiena ,ce contine 6mmoli ,reactioneaza cu o solutie de Br2 de concentratie 4%.Stiind ca toata cantitatea de butadiena se transforma in
compus tetrabromurat si carandamentul aditiei este de 80%,calculati masa de solutie de Br2 necesara reactiei.

Answer 1

CH2=CH-CH=CH2 + 2Br2 => CH2(Br)-CHBr-CHBr-CH2Br

1 mmol C4H6........2 mmoli Br2
6 mmoli C4H6......x=12 mmoli Br2

n(eta)=np/nt*100=>np=80*12/100=9,6 mmoli Br2

m Br2 =9,6*160=1536mg

C=md/ms*100=>ms=153600/4=38400mg=38,4g Br2