Question

o proportie cu mezii 2 si p, unde p este un numar natural prim impar este​

Answer 1

O proporție cu mezii 2 si p unde p este un număr natural prim impar, este  $\bf \dfrac{1}{\red{2}} =\dfrac{\red{17}}{34}$

Explicație pas cu pas:

p = număr prim impar ⇒ p ∈ {3, 5, 7, 11, 13, 17, 19, 23, 29, ......}

$\bf \dfrac{\blue{a}}{\red{b}} =\dfrac{\red{c}}{\blue{d}}~;~~ \red{b, ~c~\rightarrow mezi}~~~~\blue{a, ~d~\rightarrow extremi}$

$\boxed{\bf ~\dfrac{1}{\red{2}} =\dfrac{\red{p}}{2p}~}$

Exemple:

$\bf \dfrac{1}{\red{2}} =\dfrac{\red{3}}{2\cdot3}\implies \dfrac{1}{\red{2}} =\dfrac{\red{3}}{6}$

$\bf \dfrac{1}{\red{2}} =\dfrac{\red{5}}{2\cdot5}\implies \dfrac{1}{\red{2}} =\dfrac{\red{5}}{10}$

$\bf \dfrac{1}{\red{2}} =\dfrac{\red{7}}{2\cdot7}\implies \dfrac{1}{\red{2}} =\dfrac{\red{7}}{14}$

$\bf \dfrac{1}{\red{2}} =\dfrac{\red{11}}{2\cdot11}\implies \dfrac{1}{\red{2}} =\dfrac{\red{11}}{22}$

$\bf \dfrac{1}{\red{2}} =\dfrac{\red{13}}{2\cdot13}\implies \dfrac{1}{\red{2}} =\dfrac{\red{13}}{26}$      

$\bf \dfrac{1}{\red{2}} =\dfrac{\red{17}}{2\cdot17}\implies \dfrac{1}{\red{2}} =\dfrac{\red{17}}{34}$

==pav38==

Answer 2

$\it \dfrac{1}{2}=\dfrac{\bf7}{14}$