Question

o sarma de otel cu masa de 3g contine 1,7% carbon.masa de carbon continuta in sarma este
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Answer 1

$m_S=3 \ g \\ c=1,7\% \\ c=\frac{m_C}{m_S}\cdot 100\% \\ \Rightarrow \frac{m_C}{3 \ g} \cdot 100\%=1,7\% \\ \Rightarrow m_C=\frac{3 \ g \cdot 1,7}{100}=\frac{5,1 \ g}{100} \\ \Rightarrow \boxed{m_C=0,051 \ g}$

Answer 2

Răspuns:

ms=3g

C=1,7%

mcarbon=?

md= C× ms/100=3×1,7/100=0,051g

mcarbon=0,051g